JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    Two small magnets each of magnetic moment \[10\text{ }A{{m}^{2}}\] are placed in end on position 0.1 m apart from their centres. The force acting between them is:

    A)  \[0.6\text{N}\]   

    B)                                                                         \[0.06\text{N}\]             

    C)         \[0.06\times {{10}^{7}}\text{N}\]    

    D)         \[0.6\times {{10}^{7}}\text{N}\]

    Correct Answer: B

    Solution :

    \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{6{{M}_{1}}{{M}_{2}}}{{{r}^{4}}}={{10}^{-7}}\frac{6\times 10\times 10}{{{(0.1)}^{4}}}\] \[=0.06\,N\]


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