A) \[\left( \frac{\pi }{6} \right)\text{rad}\,{{\text{s}}^{\text{-1}}}\]
B) \[\left( \frac{\pi }{60} \right)\text{rad}\,{{\text{s}}^{\text{-1}}}\]
C) \[\left( \frac{\pi }{30} \right)\text{rad}\,{{\text{s}}^{\text{-1}}}\]
D) \[\left( \frac{\pi }{15} \right)\text{rad}\,{{\text{s}}^{\text{-1}}}\]
Correct Answer: C
Solution :
Angular velocity \[=\frac{\Delta \theta }{\Delta t}=\frac{2\pi }{60}rad\,{{s}^{-1}}\] \[=\frac{\pi }{30}rad\,{{s}^{-1}}\] Reason: A second hand makes an angle of\[2\pi \] (i.e.,\[360{}^\circ \]) in one minute, (i.e., 60 second)
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