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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    The moment of inertia of a body about a Given axis \[1.2\,\,kg\,\,{{m}^{2}}\]. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500 J and angular acceleration of \[25\,\,rad\,/{{s}^{2}}\] must be applied about the axis for a duration of:

    A)  10 s                                      

    B)  8 s                         

    C)  2 s                         

    D)         4 s

    Correct Answer: C

    Solution :

    Kinetic energy is given by \[E=\frac{1}{2}I{{\omega }^{2}},\]            \[{{\omega }^{2}}=\frac{2E}{I}\] \[{{\omega }^{2}}=\frac{2\times 1500}{1.2}=2500\] \[\omega =\sqrt{2500}=50\,rad\text{/}\sec \]    \[t=\frac{\omega }{\alpha }=\frac{50}{25}=2\,\sec \]


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