A) methane
B) ethane
C) ethylene
D) acetylene
Correct Answer: C
Solution :
In ethylene \[{{H}_{2}}C==C{{H}_{2}},\] the C?C bond distance is 1.34\[\overset{\text{o}}{\mathop{\text{A}}}\,\], therefore, the \[\pi \]electrons of the double bond are easily exposed to the reactant (electrophiles) which readily react. In acetylene molecule \[HC\equiv \equiv CH,\]although there are two \[\pi \]bonds but these electrons are not exposed to the attacking reagents due to small bond distance of \[C\equiv C\] bond (1.20\[\overset{\text{o}}{\mathop{\text{A}}}\,\]). A catalyst mercuric ion is therefore needed in reactions with actylene.
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