A) \[0.715\text{ }kg\,{{m}^{-3}}\]
B) \[1.43\,kg\,{{m}^{-3}}\]
C) \[2.86\text{ }kg\,{{m}^{-3}}\]
D) \[4.26\text{ }kg\text{ }{{m}^{-3}}\]
Correct Answer: B
Solution :
We have \[d=\frac{PM}{RT}\] or \[\frac{{{d}_{1}}{{T}_{1}}}{{{P}_{1}}}=\frac{{{d}_{2}}{{T}_{2}}}{{{P}_{2}}}\] According to the equation, \[{{d}_{1}}=2.86\,kg\,{{m}^{-3}},\] \[{{d}_{2}}=?\] \[{{T}_{1}}=273\,K\] \[{{T}_{2}}=819+273=1092\,K\] \[{{P}_{1}}=1\,atm\] \[{{P}_{2}}=2\,atm\] \[\therefore \] \[\frac{2.86\times 273}{1}=\frac{{{d}_{2}}\times 1092}{2}\] or \[{{d}_{2}}=\frac{2\times 2.86\times 273}{1092}\] \[=1.43\,kg\,{{m}^{-3}}\]
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