JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    The displacement of the motion of a particle is represent by a equation \[y=A\,\sin \,\omega t+B\,\cos \,\omega t\]The motion of particle is:        

    A)  SHM with amplitude \[\sqrt{{{A}^{2}}+{{B}^{2}}}\]

    B)  SHM with amplitude \[A+B\]

    C)  SHM with amplitude\[A\]

    D)  Oscillatory but not in SHM

    Correct Answer: A

    Solution :

    \[y=A\sin \omega t+B\cos \omega t\]                    ?(1) let           \[A=a\cos \phi \]                                              ?(2) \[B=a\cos \phi \]                                              ?(3) then equation (1) becomes \[y=a\cos \phi \sin \omega t+a\sin \phi \cos \omega t\] \[y=a\sin \,(\omega t+\phi )\]                   ?(4) It is clear that the equation number (2) in simple harmonic motion with amplitude a squaring and adding (2) and (3), we get \[{{A}^{2}}+{{B}^{2}}\le {{a}^{2}}(co{{s}^{2}}\phi +si{{n}^{2}}\phi )\] \[a=\sqrt{{{A}^{2}}+{{B}^{2}}}\]


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