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JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J, then the amount of external work done is:

    A)  180 J                                    

    B)  70 J                       

    C)  110 J                    

    D)         30 J

    Correct Answer: B

    Solution :

    Heat added to the system \[\Delta Q=110J\] Internal energy \[\Delta U=40J\] External work done is given by  \[\Delta W=\Delta Q-\Delta U=110-40\]                         \[=70\,J\]


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