JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    The peak value of alternating current is \[5\sqrt{2}\] ampere. The mean square value of current will be :

    A)  5 A            

    B)                                         2.5 A                    

    C)         \[5\sqrt{2}\]                                     

    D)         none of these

    Correct Answer: A

    Solution :

    Here: \[{{I}_{0}}=5\sqrt{2}A\] Root mean square value of current \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=\frac{5\sqrt{2}}{\sqrt{2}}=5A\]


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