A) \[1.7\times {{10}^{3}}\text{J}\]
B) \[10.7\times {{10}^{3}}\text{J}\]
C) \[3.4\times {{10}^{3}}\text{J}\]
D) \[6.8\times {{10}^{3}}\text{J}\]
Correct Answer: C
Solution :
According to kinetic theory, K.E. of 1g-mole of and ideal gas, \[E=\frac{3}{2}RT\] Hence, K.E. at normal temperature \[0{}^\circ C=273K\] or \[E=\frac{3}{2}\times 8.31\times 273=3.4\times {{10}^{3}}J\]
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