A) 94.21 nm
B) 91.16 nm
C) 911.6 nm
D) 933.6 nm
Correct Answer: B
Solution :
For Lyman series, \[\frac{1}{\lambda }=R\left( \frac{1}{{{(1)}^{2}}}-\frac{1}{{{n}^{2}}} \right)\] hence, for \[\lambda \] to be smallest, \[n\] should be greatest (i.e.,\[\infty \]).
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