JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    The earth of mass \[=6\times {{10}^{24}}\] kg revolves around the sun with an angular velocity of \[2\times {{10}^{8}}\] rad/s in a circular orbit of radius\[1.5\times 10\text{ }km\]. The force exerted by the sun on earth is :

    A)  \[6\times {{10}^{19}}N\]                             

    B)  \[18\times {{10}^{25}}N\]          

    C)         \[36\times {{10}^{21}}N\]          

    D)         \[27\times {{10}^{39}}N\]

    Correct Answer: C

    Solution :

    Here: Mass of earth \[{{M}_{e}}=6\times {{10}^{24}}kg\] Angular velocity of earth \[\omega =2\times {{10}^{-7}}rad\text{/}s\] Radius of circular orbit \[R=1.5\times {{10}^{8}}km\]     \[=1.5\times {{10}^{11}}m\] Force exerted on the earth by the sun is given by \[F={{M}_{e}}R{{\omega }^{2}}\]     \[=6\times {{10}^{24}}\times 1.5\times {{10}^{11}}\times {{(2\times {{10}^{-7}})}^{2}}\]     \[=36\times {{10}^{21}}N\]


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