A) \[2.4\times {{10}^{-12}}\text{N}\]
B) \[4.8\times {{10}^{-12}}\text{N}\]
C) \[1.2\times {{10}^{-12}}\text{N}\]
D) \[7.2\times {{10}^{-12}}\text{N}\]
Correct Answer: A
Solution :
Here: \[q=1.6\times {{10}^{-19}}C,\]\[B=1.5\,Wb\text{/}{{m}^{2}},\] \[\upsilon =2\times {{10}^{7}}m\text{/}s,\] \[\theta =30{}^\circ \] or \[\sin 30{}^\circ =\frac{1}{2}\] Force on proton is given by \[F=qv\,B\sin \theta \] \[=1.6\times {{10}^{-19}}\times 2\times {{10}^{7}}\times 1.5\times \frac{1}{2}\] \[=2.4\times {{10}^{-12}}N\]You need to login to perform this action.
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