A) \[Pb{{O}_{2}}\]
B) \[Mn{{O}_{2}}\]
C) \[N{{a}_{2}}{{O}_{2}}\]
D) \[Ti{{O}_{2}}\]
Correct Answer: C
Solution :
Peroxides give hydrogen peroxide, on treatment with dilute acids. Hence, only sodium peroxide \[\left( N{{a}_{2}}{{O}_{2}} \right)\] will give\[{{H}_{2}}{{O}_{2}}\].
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