A) \[BC{{l}_{3}}\]
B) \[PC{{l}_{3}}\]
C) \[BeC{{l}_{2}}\]
D) None of these
Correct Answer: B
Solution :
\[Cl--\underset{\centerdot \,\,\,\centerdot }{\overset{Cl}{\mathop{\overset{|}{\mathop{P}}\,}}}\,--Cl\] \[(lps+\sigma \text{-}bps=1+3=4)\] hence, hybridisation\[=s{{p}^{3}}\] \[PC{{l}_{3}}\] has \[s{{p}^{3}}\] hybridisation but due to presence of one lone pair, it is pyramidal in geometry. (Inspite of being tetrahedral)
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