JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    A closed argon pipe and an open argon pipe are tuned to the same fundamental frequency. What is the ratio of their lengths?

    A)  1 : 2           

    B)                        2 : 1                      

    C)  2 : 3                      

    D)         4 : 3

    Correct Answer: A

    Solution :

    Avoiding end correction, the length of closed organ pipe is \[{{l}_{1}}=\frac{{{\lambda }_{1}}}{4}\] or  \[{{l}_{1}}=4{{l}_{1}}\] The length of open organ pipe is \[{{l}_{2}}=\frac{{{\lambda }_{2}}}{2}\]  or  \[{{\lambda }_{2}}=2{{l}_{2}}\] Here,     \[{{n}_{1}}={{n}_{2}}\] So,          \[\frac{\upsilon }{{{\lambda }_{1}}}=\frac{\upsilon }{{{\lambda }_{2}}}\] or  \[\frac{\upsilon }{4{{l}_{1}}}=\frac{\upsilon }{2{{l}_{2}}}\] Therefore, \[{{l}_{1}}:{{l}_{2}}=1:2\]


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