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JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    A monoatomic gas supplied the heat Q very slowly keeping the pressure constant. The work done by the gas will be:

    A)  \[\frac{2}{3}Q\]              

    B)                         \[\frac{3}{5}Q\]                              

    C)  \[\frac{2}{5}Q\]                              

    D)         \[\frac{1}{5}Q\]

    Correct Answer: A

    Solution :

    For monoatomic gas at constant pressure \[\frac{\Delta U}{Q}=\frac{1}{3}\] or \[\Delta U=\frac{Q}{3}\] Now applying first law of thermodynamics \[W=\Delta Q-\Delta U\] \[=Q-\,\frac{Q}{3}\,=\frac{2Q}{3}\]


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