A) \[B{{i}_{2}}{{S}_{3}}\]
B) \[A{{g}_{2}}S\]
C) \[CoS\]
D) \[PbS\]
Correct Answer: B
Solution :
Solubilities of salts are as follows: \[B{{i}_{2}}{{S}_{3}}=\sqrt[5]{\frac{{{K}_{sp}}}{108}}\] \[=\sqrt[5]{\frac{1.6\times {{10}^{-72}}}{108}}\] \[=1.7\times {{10}^{-15}}\] \[A{{g}_{2}}S=\sqrt[3]{\frac{{{K}_{sop}}}{4}}\] \[=\sqrt[3]{\frac{1.6\times {{10}^{-49}}}{4}}\] \[=3.4\times {{10}^{-17}}\] \[PbS=\sqrt{{{K}_{sp}}}=\sqrt{1.1\times {{10}^{-29}}}\] \[=3.3\times {{10}^{-15}}\] \[CoS=\sqrt{{{k}_{sp}}}=\sqrt{2\times {{10}^{-27}}}\] \[=4.5\times {{10}^{-14}}\] Hence, \[A{{g}_{2}}S\] is least soluble. So minimum solubility is of \[CoS\] as its force of attraction is greatest.
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