A) \[sp,\,sp\]
B) \[s{{p}^{2}},\,\,s{{p}^{2}}\]
C) \[s{{p}^{2}},\,\,sp\]
D) \[s{{p}^{3}},\,\,s{{p}^{2}}\]
Correct Answer: C
Solution :
In this compound carbon atoms have following hybridization: \[\begin{align} & \overset{1}{\mathop{C{{H}_{2}}}}\,=\overset{2}{\mathop{C}}\,=C{{H}_{2}} \\ & \,\,s{{p}^{2}}\,\,\,\,\,\,\,\,\,\,sp \\ \end{align}\] Carbon one contains one \[\pi \] bond and carbon two contains two \[\pi \] bonds and hence show \[s{{p}^{2}}\] and \[sp\] hybridization respectively.
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