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JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    \[{{C}_{(dia)}}+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\]    \[\Delta H=-395.4\,\,kJ\text{/}mole\] \[{{C}_{(gr)}}+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\]     \[\Delta H=-393.5\,\,kJ\text{/}mole\] \[{{C}_{(gr)}}\xrightarrow{{}}{{C}_{(dia)}};\]             \[\Delta H=?\]

    A)  -3.8                      

    B)         -1.9                      

    C)  +3.8                     

    D)         +1.9

    Correct Answer: D

    Solution :

    \[C(dia)+{{O}_{2}}\to C{{O}_{2}}\] \[(\Delta H=-395.4\,\,kJ\text{/}mole)\] ?(i) \[C(gr)+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}\] \[(\Delta H=-\,393.5\,kJ\text{/}mole)\]                 ?(2) subtracting eq. (i) from (ii), we have \[C(gr)\xrightarrow{{}}C(dia);\] \[(\Delta H=+\,1.9\,kJ\text{/}mole)\] \[[\because \,\Delta H=-\,393.5-(-395.4)=+1.9\,kJ\,mo{{l}^{-1}}]\]


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