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JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    How much chlorine will be liberated on passing one ampere current for 30 min. through \[NaCl\] solution?

    A)  0.66 mole     

    B)         0.33 mole          

    C)         0.66 g                  

    D)         0.33 g

    Correct Answer: C

    Solution :

    According to Faradays law \[\frac{w}{E}=\frac{it}{96500}\] or,          \[\frac{w}{35.5}=\frac{1\times 30\times 60}{96500}\]     \[\Rightarrow \]               \[=0.662\,g\] so, 0.662 g chlorine is liberated.


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