A) \[K=[Ar]\,\,4{{s}^{1}}\]
B) \[Cr=[Ar]\,\,3{{d}^{5}},\,\,4{{s}^{1}}\]
C) \[Cr=[Ar]\,\,3{{d}^{4}},\,\,4{{s}^{2}}\]
D) \[Cu=[Ar]\,\,3{{d}^{10}},\,\,4{{s}^{1}}\]
Correct Answer: C
Solution :
The correct configurations of K, Cu and Cr are \[[Ar]\,4{{s}^{1}},\,\,[Ar]\,3{{d}^{10}}4{{s}^{1}},\,[Ar]\,3{{d}^{5}}4{{s}^{1}}\]respectively. As half filled and completely filled d orbitals are more stable, hence in case of Cr and Cu one electron shifts from 4s orbital to 3d orbital to give them stable electronic configuration.
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