A)
\[\frac{{{\mu }_{0}}Ni{{R}^{2}}}{2{{({{R}^{2}}+{{x}^{2}})}^{3/2}}}\]
B) \[\frac{{{\mu }_{0}}Ni}{2R}\]
C) \[\frac{{{\mu }_{0}}Ni{{R}^{2}}}{{{(R+x)}^{2}}}\]
D) zero
Correct Answer: A
Solution :
From the formula, magnetic field intensity at point P, shown in given figure while coil carry current \[i\] and having \[N\] turns is given by \[\frac{{{\mu }_{0}}Ni{{R}^{2}}}{2\,{{({{R}^{2}}+{{x}^{2}})}^{3/2}}}\]
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