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JIPMER Jipmer Medical Solved Paper-2006

  • question_answer
    \[A+B=C+D.\] If initially the concentration of A and B are both equal but at equilibrium, concentration of D will be twice of that of A, then what will be the equilibrium constant of reaction?

    A)  4/9                       

    B)         9/4                       

    C)  1/9                       

    D)         4

    Correct Answer: D

    Solution :

    \[\underset{x}{\mathop{A}}\,\,\,\,+\underset{x}{\mathop{\,\,B}}\,\,\,\,\,=\underset{\,\,\,\,\,2x}{\mathop{\,\,\underset{0}{\mathop{C}}\,}}\,+\underset{2x\,(At\,equilibrium)}{\mathop{\underset{0\,(Initial)}{\mathop{D}}\,}}\,\] \[{{K}_{c}}=\frac{[C]\,\,[D]}{[A]\,\,[B]}=\frac{2x\times 2x}{x\times x}=4\]


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