A) \[3T\]
B) \[3/2T\]
C) \[4T\]
D) \[2T\]
Correct Answer: A
Solution :
Time period \[T=2\pi \sqrt{\frac{l}{g}}\] i.e., time period does not depend on the mass of the bob. \[\therefore \] \[T\propto \sqrt{l}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{l}_{1}}}{{{l}_{2}}}}\] \[\Rightarrow \] \[\frac{T}{{{T}_{2}}}=\sqrt{\frac{l}{9l}}\] \[\therefore \] \[{{T}_{2}}=3T\]
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