A) 4/9
B) 9/4
C) 1/9
D) 4
Correct Answer: D
Solution :
\[\underset{x}{\mathop{A}}\,\,\,\,+\underset{x}{\mathop{\,\,B}}\,\,\,\,\,=\underset{\,\,\,\,\,2x}{\mathop{\,\,\underset{0}{\mathop{C}}\,}}\,+\underset{2x\,(At\,equilibrium)}{\mathop{\underset{0\,(Initial)}{\mathop{D}}\,}}\,\] \[{{K}_{c}}=\frac{[C]\,\,[D]}{[A]\,\,[B]}=\frac{2x\times 2x}{x\times x}=4\]You need to login to perform this action.
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