A) 3 Hz
B) 2 Hz
C) 4 Hz
D) 1Hz
Correct Answer: D
Solution :
Maximum speed of a particle executing SHM is \[{{u}_{\max }}=a\,\omega =a(2\pi n)\] \[\Rightarrow \] \[n=\frac{{{u}_{\max }}}{2\pi a}\] Here, \[{{u}_{\max }}=31.4\,cm\text{/}s,\]\[a=5\,cm\] Substituting, the given values, we have \[n=\frac{31.4}{2\times 3.14\times 5}=1\,Hz\]
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