A) \[0.2\,\Omega \]
B) \[5\,\Omega \]
C) \[0.4\,\Omega \]
D) \[0.04\,\Omega \]
Correct Answer: D
Solution :
Power \[P={{t}^{2}}R\] \[\Rightarrow \] \[R=\frac{P}{{{i}^{2}}}\] Given, \[P=1\,W,\]\[i=5A\] \[\therefore \] \[R=\frac{1}{{{(5)}^{2}}}=0.04\,\Omega \]
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