A) Exothermic and decreasing disorder
B) Endothermic and increasing disorder
C) Exothermic and increasing disorder
D) Endothermic and decreasing disorder
Correct Answer: C
Solution :
If reaction is exothermic, therefore, \[\Delta H\] is -ve and on increasing disorder, \[\Delta S\] is +ve thus, at these condition, \[\Delta G\] is negative according to following equation. \[\Delta G=\Delta H-T\Delta S\] \[\Delta G=-ve\,.\] Hence, for spontaneous reaction \[\Delta G\] must be - ve.
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