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JIPMER Jipmer Medical Solved Paper-2008

  • question_answer
    The volume of a gas measured at \[27{}^\circ C\] and 1 atm pressure is 10 L. To reduce the volume to 2 L at 1 atm pressure, the temperature required is

    A)  60 K      

    B)                         75 K                      

    C)  150 K                   

    D)         225 K

    Correct Answer: A

    Solution :

    Here \[{{V}_{1}}=10L,\] \[{{V}_{2}}=2L\] \[{{p}_{1}}=1\,atm,\] \[{{p}_{2}}=1\,atm\] \[{{T}_{1}}=300\,K,\,{{T}_{2}}=?\] \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{1\times 10}{300}=\frac{1\times 2}{{{T}_{2}}}\]                     \[{{T}_{2}}=\frac{300\times 2}{10}=60\,K\]


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