A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Correct Answer: D
Solution :
If m is the mass of a substance deposited or liberated at an electrode during electrolysis when a charge q passes through electrolyte, then according to Faradays first law of electrolysis, \[m\propto q\] or \[m=zq\] where z is a constant of proportionality and is called electrochemical equivalent (ECE) of the substance. If an electric current \[I\] flows through the electrolyte, then \[q=It\] \[\therefore \] \[m=zit\] Here, \[i=1.5A,\]\[t=10\,\min =10\times 60\,s,\] \[z=30\times {{10}^{-5}}g\,{{C}^{-1}}\] Hence, mass of copper deposited on the electrode \[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] \[=27\times {{10}^{-2}}=0.27g\]
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