A) 22 dyne
B) 20 N
C) 20 dyne
D) 100 N
Correct Answer: B
Solution :
The accelerating force on the rocket = upward thrust\[=\frac{\Delta \,m}{\Delta t}\cdot u\] Given, \[\frac{\Delta \,m}{\Delta t}=50\times {{10}^{-3}}kg\text{/}s,\,v=400\,m\text{/}s\] So, accelerating force\[=50\times {{10}^{-3}}\times 400\] \[=20N\]
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