A) \[{{K}_{c}}=\frac{{{[A]}^{1/2}}{{[B]}^{1/3}}}{{{[C]}^{3/2}}}\]
B) \[{{K}_{c}}=\frac{{{[C]}^{3/2}}}{{{[A]}^{2}}{{[B]}^{3}}}\]
C) \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}\]
D) \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}+{{[B]}^{1/3}}}\]
Correct Answer: C
Solution :
\[\frac{1}{2}A(g)+\frac{1}{3}B(g)\frac{2}{3}C(g)\] Equilibrium constant, \[{{K}_{c}}=\frac{\text{Rate product}}{\text{Rate of reactant}}\] \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}\]
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