A) \[{{S}_{N}}\] 1 mechanism
B) \[{{S}_{N}}\] 2 mechanism
C) Any of (a) and (b)
D) None of these
Correct Answer: A
Solution :
Tertiary halide preferentially undergo \[{{S}_{N}}\]1 substitution as they can give stable carbocation. \[\underset{t\text{-}butyl\,chloride}{\mathop{{{H}_{3}}C-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Cl}}\,\xrightarrow[-Cl]{slow}\underset{\begin{smallmatrix} 3{}^\circ \,carbocation \\ \,\,(most\,stable) \end{smallmatrix}}{\mathop{{{({{H}_{3}}C)}_{3}}{{C}^{+}}}}\,\xrightarrow[fast]{+O{{H}^{-}}}\] \[\underset{t\text{-}butyl\,alcohol}{\mathop{{{({{H}_{3}}C)}_{3}}COH}}\,\]
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