JIPMER Jipmer Medical Solved Paper-2009

  • question_answer
    The most probable velocity (in cm/s) of hydrogen molecule at \[27{}^\circ C\] will be

    A)  \[19.3\times {{10}^{4}}\]                            

    B)  \[17.8\times {{10}^{4}}\]            

    C)         \[24.93\times {{10}^{9}}\]          

    D)         \[17.8\times {{10}^{8}}\]

    Correct Answer: B

    Solution :

    Most probable velocity\[=\sqrt{\frac{8RT}{\pi m}}\] \[T=(27+273)=300\,K\] Molecular mass of\[{{H}_{2}}=2g\,mo{{l}^{-1}}\] \[=\sqrt{\frac{8\times 8.314\times {{10}^{7}}\times 300}{3.14\times 2}}\] \[=17.8\times {{10}^{4}}\,cm\text{/}s.\]


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