A) 24,630 \[c{{m}^{-1}}\]
B) 24,360 \[c{{m}^{-1}}\]
C) 24,730 \[c{{m}^{-1}}\]
D) 24, 372 \[c{{m}^{-1}}\]
Correct Answer: D
Solution :
\[\bar{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series \[{{n}_{1}}=2\] and for 4th line in Balmer series \[{{n}_{2}}=6\] \[\because \] \[R=109677\,c{{m}^{-1}}\] \[\bar{v}=109677\,\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{6}^{2}}} \right)\] \[=109677\,\left( \frac{1}{4}-\frac{1}{36} \right)\] \[\bar{v}=24,\,372\,c{{m}^{-1}}\]
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