JIPMER Jipmer Medical Solved Paper-2010

  • question_answer
    In a series L-C-R circuit, resistance R = 10\[\Omega \] and the impedance Z = 10\[\Omega .\] The phase difference between the current and the voltage is

    A)  \[0{}^\circ \]                     

    B)         \[30{}^\circ \]                  

    C)         \[45{}^\circ \]                  

    D)         \[60{}^\circ \]

    Correct Answer: A

    Solution :

    Impedance, \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[\therefore \]  \[10=\sqrt{{{(10)}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[\Rightarrow \]               \[100=100+{{({{X}_{L}}-{{X}_{C}})}^{2}}\] \[\Rightarrow \]               \[{{X}_{L}}-{{X}_{C}}=0\]                                               ?(i) Let\[\phi \]is the phase difference between current and voltage \[\therefore \]  \[\tan \phi =\frac{{{X}_{L}}-{{X}_{C}}}{R}\] \[\therefore \]  \[\tan \phi =\frac{0}{R}\] \[\Rightarrow \]                     \[\phi =0\]                    [from Eq. (i)]


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