A) \[1.6\times {{10}^{-17}}\text{J}\]
B) \[1.6\times {{10}^{-14}}\text{J}\]
C) \[1.6\times {{10}^{-10}}\text{J}\]
D) \[1.6\times {{10}^{-8}}\text{J}\]
Correct Answer: A
Solution :
\[KE=eV=1.6\times {{10}^{-19}}\times 100=1.6\times {{10}^{-17}}J\]
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