JIPMER Jipmer Medical Solved Paper-2010

  • question_answer
    Wavelength of light emitted from second orbit to first orbit in a hydrogen atom is

    A)  \[6563\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B)                         \[4102\,\overset{\text{o}}{\mathop{\text{A}}}\,\]        

    C)         \[4861\,\overset{\text{o}}{\mathop{\text{A}}}\,\]        

    D)         \[1215\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

    Wavelength of light \[\frac{1}{\lambda }=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)\] \[\Rightarrow \]               \[\frac{1}{\lambda }=1.097\times {{10}^{7}}\times \frac{3}{4}\] \[\therefore \]  \[\lambda =1.215\times {{10}^{-7}}m=1215\overset{\text{o}}{\mathop{\text{A}}}\,\]


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