A) 20
B) 16
C) 12
D) 8
Correct Answer: A
Solution :
The structure of \[{{H}_{2}}S{{O}_{4}}\] is \[\text{H}--\text{\underset{\scriptscriptstyle\centerdot\centerdot}{\ddot{O}}}--\underset{\text{:}\,\,\text{\underset{\scriptscriptstyle\centerdot\centerdot}{O}}\,\text{:}}{\overset{\text{:\ddot{O}}\,\text{:}}{\mathop{\underset{\text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ }}{\overset{\text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ }}{\mathop{\text{s}}}}\,}}}\,--\text{\ddot{\underset{\scriptscriptstyle\centerdot\centerdot}{O}}}--\text{H}\] Total number of unshared electrons \[=10\times 2=20\]
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