A) \[1{{s}^{2}},2{{s}^{1}}\]
B) \[1{{s}^{2}},2{{s}^{2}},2{{p}^{3}}\]
C) \[1{{s}^{2}},2{{s}^{2}},2{{p}^{2}}\]
D) \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{1}}\]
Correct Answer: B
Solution :
The ionization energy of \[1{{s}^{2}},2{{s}^{2}},2{{p}^{3}}\] configuration is highest due to the presence of half-filled (stable) orbitals.
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