A) \[\text{2 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{9}}}\,\text{N}{{\text{m}}^{\text{-2}}}\]
B) \[\text{4 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{9}}}\,\text{N}{{\text{m}}^{\text{-2}}}\]
C) \[\text{8 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{9}}}\,\text{N}{{\text{m}}^{\text{-2}}}\]
D) \[\text{16 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{9}}}\,\text{N}{{\text{m}}^{\text{-2}}}\]
Correct Answer: A
Solution :
Shearing modulus of cube \[\eta =\frac{Fl}{A\Delta l}=\frac{8\times {{10}^{3}}\times 40\times {{10}^{-3}}}{{{(40\times {{10}^{-3}})}^{2}}\times {{(0.1\times 10)}^{-3}}}\] \[=2\times {{10}^{9}}N{{m}^{-2}}\]
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