A) \[+I\]group stabilises a carbocation
B) \[+I\] group stabilises a carbanion
C) \[-I\] group stabilises a carbocation
D) \[-I\] group stabilises a free radical
Correct Answer: A
Solution :
\[+I\]group (i.e., electron donating groups) stabilised the carbocation. \[+I\] and \[-I\] groups destabilised the carbanion and carbocations respectively. \[+I\] groups stabilised the free radicals but \[-I\] group destabilised them.
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