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JIPMER Jipmer Medical Solved Paper-2010

  • question_answer
    A solid AB has the\[NaCl\]structure. If radius of cation \[{{A}^{+}}\] is 120 pm, the maximum possible value of the radius of the anion \[{{B}^{-}}\]is

    A)  240 pm               

    B)  60 pm                  

    C)  49.6 pm        

    D)         290 pm

    Correct Answer: D

    Solution :

    For \[NaCl\] crystal, Radius of cation/radius of anion = 0.414 \[\frac{{{r}_{{{A}^{+}}}}}{{{r}_{{{B}^{-}}}}}=0.414\] \[{{r}_{{{B}^{-}}}}=\frac{{{r}_{{{A}^{+}}}}}{0.414}=\frac{120}{0.414}\] = 290 pm


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