A) \[{{K}_{2}}S{{O}_{4}}\cdot A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24\,{{H}_{2}}O\]
B) \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot FeS{{O}_{4}}\cdot 6{{H}_{2}}O\]
C) \[{{K}_{2}}S{{O}_{4}}\cdot C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24\,{{H}_{2}}O\]
D) \[{{K}_{2}}S{{O}_{4}}\cdot F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24\,{{H}_{2}}O\]
Correct Answer: A
Solution :
Common alum is\[{{K}_{2}}S{{O}_{4}}\cdot A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\cdot 24{{H}_{2}}O.\]
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