A) 30 N
B) 150 N
C) 300 N
D) 600 N
Correct Answer: C
Solution :
Pressure at neck of bottle \[{{p}_{1}}=\frac{{{F}_{1}}}{{{A}_{1}}}=\frac{{{F}_{1}}}{\pi r_{1}^{2}}\] Similarly, pressure at bottom of bottle \[{{p}_{2}}=\frac{{{F}_{2}}}{{{A}_{2}}}=\frac{{{F}_{2}}}{\pi r_{2}^{2}}\] According to Pascals law, liquids transmit pressure equal in all directions. \[\therefore \] \[\frac{{{F}_{1}}}{\pi r_{1}^{2}}=\frac{{{F}_{2}}}{\pi r_{2}^{2}}\] \[\frac{12}{\pi {{(3)}^{2}}}=\frac{{{F}_{2}}}{\pi {{(15)}^{2}}}\] \[{{F}_{2}}=\frac{12\times 15\times 15}{3\times 3}\] \[{{F}_{2}}=300\,N\]
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