A) 1
B) 2
C) 4
D) 6
Correct Answer: A
Solution :
Decrease in atomic number and mass number due to emission of one \[\alpha \]-particle is 2 and 4 respectively, and atomic number is increased by 1 due to emission of one \[\beta \text{-}\]particle. Here, decrease in mass number = 238 - 222 = 16. So, number of a-particle emitted\[=\frac{16}{4}=4.\] Atomic number due to emission of 4\[\alpha \text{-}\]particle\[=90-2\times 4=82\]. Increase in atomic number due to\[\beta \text{-}\]particle emission = 83 - 82 = 1. Hence, number of \[\beta \text{-}\]particle emitted =1.
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