A) \[22.4\text{ }m\text{/}s\]
B) \[112\text{ }m\text{/}s\]
C) \[\frac{0.64\times 40}{1000\times 100}\,m\text{/}s\]
D) \[1000\,\,m\text{/}s\]
Correct Answer: A
Solution :
From circular motion balance condition. \[\frac{m{{v}^{2}}}{r}=\mu N\] here \[N=mg\] \[\therefore \] \[\frac{m{{v}^{2}}}{r}=\mu mg\,\,\,\Rightarrow \,\,\,{{v}^{2}}=\mu g\cdot r\] or, \[V=\sqrt{\mu g\cdot r}\] \[=\sqrt{1.28\times 9.8\times 40}\] \[=22.4\text{ }m\text{/}sec\]
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