A) 280 km/s
B) 56.0 km/s
C) 112 km/s
D) 56 km/s
Correct Answer: B
Solution :
Escape velocity from the earth surface \[{{V}_{escape}}=\sqrt{\frac{2GM}{R}}\] here, \[\sqrt{\frac{2GM}{R}}=11.2\,\,km\text{/}\sec \] when M = 100 M and R = 4R \[\therefore \] \[\text{Vescape}=\sqrt{\frac{100}{4}\frac{GM}{R}}\] \[=5\times 11.2=56\,km\text{/}\sec \]
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