JIPMER Jipmer Medical Solved Paper-2013

  • question_answer
    A gas expands 0.25 \[{{m}^{3}}\] at constant pressure W\[{{10}^{3}}N\text{/}{{m}^{2}},\]the work done is

    A)  250 N                                   

    B)  250 W

    C)  250 J                    

    D)         2.5 erg

    Correct Answer: C

    Solution :

    From the formula of work done at constant pressure \[W=P\Delta V={{10}^{3}}\times 0.25=250\text{ }J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner