A) 1 A
B) 0.5 A
C) 0.2 A
D) 0.1 A
Correct Answer: D
Solution :
The amplitudes of the two coherent light beams are\[\sqrt{4}\,A\]and\[\sqrt{1}\,A.\] At the point of constructive interference, resulting amplitude is max. 2A + A = 3A. At the point of destructive interference, resulting amplitude 2A - A = A. Hence, Maximum intensity\[={{(3A)}^{2}}=9I\] Minimum intensity\[={{(A)}^{2}}=I.\]
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